10x^2-13x-108=0

Solution for 10x^2-13x-108=0 equation:

10x^2-13x-108=0

a = 10; b = -13; c = -108;
Δ = b2-4ac
Δ = -132-4·10·(-108)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-67}{2*10}=\frac{-54}{20}
=-2+7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+67}{2*10}=\frac{80}{20}
=4
$